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Question

A particle starting from rest undergoes acceleration given by a=|t2| m/s2 where, t is time in second. Velocity of particle after 4 sec is

A
1 m/s
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B
2 m/s
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C
8 m/s
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D
4 m/s
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Solution

The correct option is D 4 m/s
As we know that,
dvdt=a
dv=a dt
Since, a=(t2), has negative value for t<2 and positive value for t>2, so, the value of function a=|t2| will be
a=(t2);t<2
and a=(t2);t>2
v0v dv=20(t2)dt+42(t2)dt
v=[t22+2t]20+[t222t]42
v=2+2=4 m/s

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