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Standard XI

Physics

Position of a point

A particle st...

Question

A particle starting from the origin $(0, 0)$ moves in a straight line in the $(x, y)$ plane. Its coordinates at a later time are $(\sqrt{3}, 3)$ . The path of the particle makes with the x-axis an angle of

45^{\circ}

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60^{\circ}

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0^{\circ}

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30^{\circ}

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Solution

The correct option is B $60^{\circ}$
Let, $θ$ be the angle which the particle makes with an x-axis.
From the given figure:
$t a n θ = \frac{3}{\sqrt{3}} = \sqrt{3} \Rightarrow θ = t a n^{- 1} \sqrt{3} = 60^{\circ}$ .
Hence, the correct answer is option (b).

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The correct option is B $60^{\circ}$
Let, $θ$ be the angle which the particle makes with an x-axis.
From the given figure:
$t a n θ = \frac{3}{\sqrt{3}} = \sqrt{3} \Rightarrow θ = t a n^{- 1} \sqrt{3} = 60^{\circ}$ .
Hence, the correct answer is option (b).