CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A PARTICLE STARTS from rest ,accelerates at 2 m/s2for 10 sec then goes for constant speed for 30 sec and then decelerates at 4 m/s2 till it stops. what is the distance travelled by it?

Open in App
Solution

u = 0a = 2m/s2t = 10ss1 = ut+ 0.5at2s1 = 0 +0.5×2×100 = 100 ms2 = vt2v = u + at = 0+20 = 20 m/ss2 = 20×30 = 600 m02-v2=2(-a)s3s3 = 400/8=50 ms = s1+s2+s3 = 100+600+50 = 750m

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Speed and Velocity
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon