A particle starts from rest. Its acceleration at time t=0 is 5ms−2 which varies with time as shown in figure. The maximum speed of the particle will be
A
7.5ms−1
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B
15ms−1
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C
30ms−1
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D
7.5ms−1
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Solution
The correct option is B15ms−1 Area under a−t graph corresponds to change in velocity
Hence A=12×5×6=Δv=v−u
As particle starts from rest u=0,
Hence v=15 m/s
Hence the correct choice is (b).