Question

A particle starts from rest with acceleration $2m/s^2$, The distance moved by the particle in 5 sec is:

• A. 22 m
• B. 28 m
• C. 25 m
• D. 13 m

Answer 1

The correct option is C 25 m

Given:

Acceleration $a=2m/s^2$

Time $t=5s$

Initial velocity $u=0$

We know from the equation of motion,

$s=ut+\frac{1}{2}a{t}^2$

$\Rightarrow s=0+\frac{1}{2}\times 2\times 5\times 5$

$s=25m$

Hence, the distance moved by the particle is $25m$