Question

A particle starts from the origin at $t=0$ with a velocity of $5\hat{i}m/s$ and moves in the $x-y$ plane with a constant acceleration of $(4\hat{i}+2\hat{j})m/s^2$. What is the $x-$ coordinate of the particle at $t=3s$?

• A. $28m$
• B. $33m$
• C. $35m$
• D. $26m$

Answer 1

The correct option is B $33m$

Given, initial velocity of the particle in $x-$ direction, $u_x=5m/s$
And acceleration, $a_x=4m/s^2$
$x-$ coordinate of the particle at $t=3s$,
$x=u_{x}t+\frac{1}{2}{a}_x{t}^2$
$x=5\left(3\right)+\frac{1}{2}\times 4\times (3{)}^2$
$x=33m$