A particle starts from the origin, goes along the x-axis to the point (20m, 0) and then returns along the same line to the point (-20 m, 0). the distance and displacement of the particle during the trip are

60 m, 20 m

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40 m, - 40 m

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40 m, 40 m

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80 m, 40 m

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Solution

The correct option is A $60 m, 20 m$
$0 \to$ Starting point /origin
$(1)$ Distance travelled by the point $= 20 + 20 + 20 = 60 m$
$(2)$ Displacement is only $O B + 20 m$ in the negative direction
Displacement $\to$ Distance between final and initial position
$(60 m, 20 m)$

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