A particle starts from the position of rest under a constant acceleration. It travels a distance x in the first 10 seconds and distance y in the next 20 seconds. Then
A
y=8x
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B
y=x
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C
y=5x
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D
y=4x
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Solution
The correct option is Ay=8x initially velocity is zero, and acceleration is a, so distance covered in 10 sec is x=12a102=50a
now distance covered in total 30 sec is x+y=12a302=450a