A particle starts from x=0 and moves along a straight line such that its velocity v depends on position x as v=x+4. Acceleration of the particle at t=0 is
A
e4m/s2
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B
4e4m/s2
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C
4m/s2
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D
0
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Solution
The correct option is C4m/s2 Velocity of the particle, v=x+4 Acceleration a=dvdt=d(x+4)dt ⇒a=v=x+4 At t=0,x=0 ∴ Acceleration at t=0is4m/s2