Question

A particle starts its motion from x = 8 at $t=0$. The $v-t$ graph of the particle is given in figure. The maximum x-coordinate of the particle is _____.

• A. 20
• B. 180
• C. 236
• D. 188

Answer 1

The correct option is C 236

The velocity of the particle is changing the sign at 24 sec. This means the particle is taking a U-turn at 24s. Therefore, the maximum X-coordinate can be observed at 24s. Displacement at 24s is the area under the graph from 0 to 24 s.
$totalarea=(\frac{1}{2}.4.8)+(8\times 6)+\frac{1}{2}6\times (8+20)+\frac{1}{2}8\times 20=228$
$△$x = 228
x - 8 = 228
x = 236