Question

A particle starts its SHM from mean position at $t=0$. If its time period is $T$ and amplitude $A$. The distance travelled by the particle in the time from $t=0$ to $t=5T/4$ is

• A. A
• B. 2A
• C. 4A
• D. 5A

Answer 1

The correct option is D 5A

In $\frac{5T}{4}$ , for the first $T$ second the distance is a complete SHM which is $4A$
In the rest of the $\frac{T}{4}$ secs it travel to the extreme position i.e $A$
$4A+A=5A$