The correct option is B Average velocity =2√3 m/s; Average speed =√3π m/s
We have, tangential acceleration at=π m/s2
Radius of circle r=6 m, time t=2√3 sec
Since, it starts from rest ω0=0
Angular displacement after time t=2√3 s is
θ=12αt2=12×atr×t2
=12×π6×(2√3)2=π rad
So, linear displacement is 2r=12 m and distance covered by particle is πr=6π m
Thus, average velocity =Total displacementTotal time taken=12t=122√3=2√3 m/s
and average speed =Total distanceTotal time taken=6π2√3=π√3 m/s