wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A particle starts moving from rest from a fixed point in a fixed direction. The distance s from the fixed point at a time t is given by s=t2+atb+17, where a and b are real numbers. If the particle comes to rest after 5s at a distance of s=25 units from the fixed point, then value of a and b are respectively.

A
10,33
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10,33
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
8,33
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10,33
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 10,33
Given,
s=t2+atb+17
After 5s,
[dsdt]t=5=[2t+a]t=5=0
a=10
At t=5s,s=25 units
25=52+5ab+17 [s=25 and t=5]
25=25+5(10)bb+17
5017=b
b=33

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rate of Change
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon