wiz-icon
MyQuestionIcon
MyQuestionIcon
5
You visited us 5 times! Enjoying our articles? Unlock Full Access!
Question

A particle starts moving rectilinearly at time t = 0 such that its velocity ‘v’ changes with time ‘t’ according to the equation v=t2t where t is in seconds and v in m/s. Find the time interval for which the particle retards.


A

t = 0 to t = 1 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

t = 0.5 s to t = 1 s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

t = 0 to t = 0.5 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

t > 1 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

t = 0.5 s to t = 1 s


Velocity, v=t2t
Acceleration, a=dvdt=2t1
The particle retards when acceleration is opposite to velocity.
Now, v is positive when t > 1 s and negative when t < 1 s.
Similarly, a is positive when t > 0.5 s and negative when t < 0.5 s.
So, for the interval t = 0.5 s to t = 1 s, velocity and acceleration have opposite signs and the particle is retarding.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Motion Under Variable Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon