A particle starts performing simple harmonic motion. Its amplitude is $A$ . At one time its speed is half that of the maximum speed. At this moment the displacement is:

\frac{\sqrt{2} A}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{\sqrt{3} A}{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{2 A}{\sqrt{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{3 A}{\sqrt{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{\sqrt{3} A}{2}$
$v = ω \sqrt{A^{2} - x^{2}}$
$∴$ $\frac{ω A}{2} = ω \sqrt{A^{2} - x^{2}}$ or $x = \frac{\sqrt{3}}{2} A$

Suggest Corrections

Similar questions

Q. A particle performs simple harmonic motion with amplitude A. Its speed is trebled at the instant that it is at a distance

\frac{2 A}{3}

from equilibrium position. The new amplitude of the motion is

Q. A particle performs simple harmonic motion with amplitude

A

. Its speed is tripled at the instant it is at a distance

\frac{2 A}{3}

from equilibrium position. The new amplitude of the motion is

A particle performs simple harmonic motion with amplitude A. Its speed is trebled at the instant that it is at a distance $\frac{2 A}{3}$ from equilibrium position. The new amplitude of the motion is:

Q. A particle performs simple harmonic motion with amplitude

A

. Its speed is tripled at the instant it is at a distance

\frac{2 A}{3}

from equilibrium position. The new amplitude of the motion is

Q. A particle executes simple harmonic motion with an amplitude of A cm. At what displacement from mean does it speed equal to

\frac{1}{3} r d

of maximum speed?

Join BYJU'S Learning Program

A particle starts performing simple harmonic motion. Its amplitude is A. At one time its speed is half that of the maximum speed. At this moment the displacement is:

The correct option is B √3A2v=ω√A2−x2∴ ωA2=ω√A2−x2 or x=√32A

A particle starts performing simple harmonic motion. Its amplitude is $A$ . At one time its speed is half that of the maximum speed. At this moment the displacement is:

The correct option is B $\frac{\sqrt{3} A}{2}$
$v = ω \sqrt{A^{2} - x^{2}}$
$∴$ $\frac{ω A}{2} = ω \sqrt{A^{2} - x^{2}}$ or $x = \frac{\sqrt{3}}{2} A$