A particle starts with an initial velocity 2.5m/s along the positive x− direction and it accelerates uniformly at the rate 0.50m/s2. The distance travelled by the particle in first two seconds will be
A
4m
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B
5m
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C
1m
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D
6m
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Solution
The correct option is D6m We have, s=ut+12at2=(2.5)(2)+12(0.50)(2)2 s=6m Hence, distance travelled by the particle is s=6m