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Question

A particle starts with an initial velocity 2.5 m/s along the positive x− direction and it accelerates uniformly at the rate 0.50 m/s2. The distance travelled by the particle in first two seconds will be

A
4 m
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B
5 m
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C
1 m
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D
6 m
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Solution

The correct option is D 6 m
We have, s=ut+12at2=(2.5)(2)+12(0.50)(2)2
s=6 m
Hence, distance travelled by the particle is s=6 m

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