Question

A particle starts with an initial velocity of $20m/s$ and moves with a constant acceleration on a straight line. If its final velocity is $60m/s$, then velocity of midpoint is

• A. $40m/s$
• B. $22\sqrt{5}m/s$
• C. $20\sqrt{5}m/s$
• D. $24\sqrt{5}m/s$

Answer 1

Answer: (C)

$20\sqrt{5}m/s$

The following velocity at the mid point is give by the formula,

$V_{midpoint}=\sqrt{\frac{(V_{initial}{)}^2+(V_{final}{)}^2}{2}}$

$V_{midpoint}=\sqrt{\frac{{20}^2+{60}^2}{2}}=\sqrt{\frac{400+3600}{2}}$

$=20\sqrt{5}m/s$