A particle stats with a velocity of 2ms−1 and moved in a straight line with a retardation of 0.1ms−2. The first time at which the particle is 15m from the starting point is:
A
10s
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B
20s
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C
30s
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D
40s
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Solution
The correct option is A10s Time to make the velocity zero and changing the direction of motion, will be given as T=ua=20.1=20sec
time needed to cover 15m will be given by s=ut−at2/2
so 15=2t−0.05t2, multiplying by 20 both sides we get t2−40t+300=0
solving it we get t=30sec and t=10sec
t=10sec is the first moment when the particle will be at 15m