Question

A particle takes "n" seconds less and acquires a velocity "u m/s" higher at one place in falling through the same distance.the product of the acceleration s due to gravity at two places is

Answer 1

we know
s = u t + 1/2 a t^2
here intial velocity = 0
distance = u ; t = n
So,
u = 1/2 s n^2

s = (2u/n)^2