Question

A particle travels $\text{10m}$ in first $\text{5sec}$ and $\text{10m}$ in next $\text{3sec}$ . Assuming constant acceleration what is the distance travelled in next $\text{2sec.}$

• A. 8.3 m
• B. 9.3 m
• C. 10.3 m
• D. None of above

Answer 1

The correct option is A 8.3 m

so the distance in last 2sec, $s_{10}-s_8⟹28.3m-$ $20m=8.3m$