Question

A particle Travels 10 m in first 5 seconds 10 m in next 3 seconds. assuming constant acceleration what is the distance travelled in next 2 seconds

Answer 1

Dear Student,
Let assume initial velocity is u and constant acceleration a.

using s=ut+ 0.5 at²

For first 5 second

10=5 u + 0.5 x a x 25..........(1)

for next 3 seconds t=8 and s=20

20=8 u + 0.5 x a x 64...........(2)

Solving 1 and 2 , we get,

a=1/3 and u=7/6

Now for next 2 seconds t=10 and s'

S'=10 x 7/6 + 0.5 x(1/3) x 100

S'=170/6

Now distance travelled in 2 sec=(170/6)-20=50/6 meter


Regards