A particle travels in a circle of radius $20$ cm at a speed that uniformly increases. If the speed changes from $5.0 m s^{- 1}$ to $6.0 m s^{- 1}$ in $2.0 s,$ find the angular acceleration.

2.5 r a d s^{- 2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3.5 r a d s^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.5 r a d s^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5.5 r a d s^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $2.5 r a d s^{- 2}$
Since speed increases uniformly , average tangential acceleration is equal to instantaneous tangential acceleration is given .
$a_{t} = \frac{d v}{d t} =$ $\frac{v_{2} - v_{1}}{t_{2} - t_{1}}$

$\frac{60 - 5.0}{2.0} m s^{- 2} = 0.5 m s^{- 2}$

The angular acceleration is $α$ = $a_{t} / r$

$\frac{0.5 m s^{- 2}}{20 c m} = 2.5 r a d s^{- 2}$

Suggest Corrections

Similar questions

A particle travels in a circle of radius 20 $c m$ at a speed that uniformly increases. If the speed changes form 5.0 $\frac{m}{s}$ to 6.0 $\frac{m}{s}$ in 2.0 $s$ , find the angular acceleration.

Q. A particle moves in a circle of radius 0.5 m at a speed that uniformly increases. Find the angular acceleration of particle if its speed changes from 2.0 m/s to 4.0 m/s in 4.0 s.

Q. The speed of a particle traveling in a circle of radius

20 c m

increases uniformly from

6.0 m / s

8.0 m / s

4.0 s

, find the angular acceleration.

Q. The speed of a particle travelling in a circle of radius

20 cm

increases uniformly from

6 m/s

8 m/s

4 sec

. The angular acceleration of particle is :

For a particle moving in a circle of radius $1 m$ , speed increases uniformly from $5 m/s$ to $10 m/s$ in $10 seconds$ . The value of angular acceleration of the particle is

Join BYJU'S Learning Program

A particle travels in a circle of radius 20cm at a speed that uniformly increases. If the speed changes from 5.0ms−1 to 6.0ms−1 in 2.0s,find the angular acceleration.

The correct option is A 2.5rads−2Since speed increases uniformly , average tangential acceleration is equal to instantaneous tangential acceleration is given .at=dvdt=v2−v1t2−t160−5.02.0ms−2=0.5ms−2The angular acceleration is α =at/r0.5ms−220cm=2.5rads−2

A particle travels in a circle of radius $20$ cm at a speed that uniformly increases. If the speed changes from $5.0 m s^{- 1}$ to $6.0 m s^{- 1}$ in $2.0 s,$ find the angular acceleration.