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Question

A particle undergoes simple harmonic motion having time-period T. The time taken 3/8th oscillation is-

A
38 T
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B
58 T
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C
512 T
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D
712 T
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Solution

The correct option is C 512 T

Time taken to complete one fourth oscillation is T4 // where T is the time period .

So time to complete 18th oscillation from to extreme position is obtained from

y=a/2=acos ωt=acos2πTt

Or, acosπ3=acos2πTt

Or,t=T6 s .

Hence time to complete 3/8th oscillation

18th+14th

=T4+T6=512T


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