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A particle wi...

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A particle will leave a vertical circle of radius r, when its velocity at the lowest point of the circle is

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Q. A particle is projected along the inner surface of a smooth vertical circle of radius

R

, its velocity at the lowest point being

\frac{1}{5} \sqrt{95 R g}

. It will leave the circle at angle

θ

with the verticle. The angle

θ

Q. A particle is projected along the inner surface of a smooth vertical circle of radius

R

, its velocity at the lowest point being

\frac{\sqrt{95 R g}}{5}

. It will leave the circle at an angular distance of______from the vertical line joining highest and lowest points.

Q. A particle of mass 10 gms performs a vertical circular motion of radius = 10 cm. The velocity at the lowest point of the circle is 5 m/s. What will be its velocity when it reaches at the middle point of the circle (i.e makes an angle zero degrees with the radius vector)

Q. A particle originally at rest at the highest point of a smooth vertical circle is slightly displaced. It will leave the circle at a vertical distance

h

below the highest point such that

Q. The minimum speed for a particle at the lowest point of a vertical circle of radius

R

to describe the circle is

v

. If the radius of the circle is reduced to one - fourth of its value, the corresponding minimum speed will be:

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