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Question

# A particle with charge 6 nC is moving in a uniform magnetic field →B=(1.23T)^az .The magnetic force on a particle is measured to be →F=(4.5×107)^ax+(7.5×107)^ayN Select the correct statement(s).

A
The dot product of velocity of particle and magnetic force is zero
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B
The component of velocity in y-direction is always zero
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C
(c)Magnetic field intensity in air is 9.78×105A/m
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D
Total force on particle when it is moving in both electric and magnetic field with electric field E=1^az volt / m is given as
(4.5×107^ax+7.5×107^ayN)
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Solution

## The correct option is D Total force on particle when it is moving in both electric and magnetic field with electric field →E=1^az volt / m is given as (4.5×107^ax+7.5×107^ayN) (a,c,d) (a) Magnetic force and velocity are always normal to each other thus dot product of them is zero (b) →F=q(→V×→B) (4.5×107^ax+7.50×107ay) = (6×10−9[(x^ax+y^ay+z^az)]×1.23^az ⇒ y-component of velocity is present so it is not zero (c) →H=Bμ0=1.234π×10−7 = 9.78 × 105 A/ m (d) →E=1^az →F = Q→E +q(→V × →B ) →F = →FE+→FM →FE = 6 ×10−9 ^azN →FM = 4.5×107^ax+7.5×107^ayN So, →F=4.5×107^ax+7.5×107^ay+6×10−6^azN

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