A particle with charge q and mass m is projected with kinetic energy K into the region between two plates of a uniform magnetic field B as shown below.
If the particle is to miss collision with the opposite plate, the maximum value of B is
A
√2Kqmd
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B
√2Kdqm
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C
√2Kmqd
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D
√2Kqmd
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Solution
The correct option is C√2Kmqd Given that, 12mv2=K ⇒v=√2Km
To just miss collision with the opposite plate, the particle must move in a radius r which is equal to d.
Now, r=mvqB⇒d=m√2KmqB
Solving we get, B=√2Kmqd