As given, energy of the particle is maximum for ω=ω2
As we know, the energy of the particle is maximum at natural frequency
⇒ω2=ω0
And amplitude of the particle is maximum for ω=ω1
For maximum amplitude, frequency of external force will be
ω=√ω20−(b2m)2
⇒ω1≠ω0
Here b is damped constant and m is mass of particle.
Final answer :(c)