A particle with uniform retardation along a straight line distances a and b in successive intervals p and q seconds. The acceleration of the particle is
A
2(aq−bp)pq(p+q)
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B
2(bp−aq)q(p+q)
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C
2(aq+bp)pq(p+q)
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D
2(aq−bp)pq(p−q)
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Solution
The correct option is A2(aq−bp)pq(p+q) Let retardation be f and initial velocity be u. For AB a=up−12fp2...(i) ap=u−fp2 For AC,a+b=u(p+q)−12f(p+q)2...(ii) a+bp+q=u−f(p+q)2