A particle X moving with a constant velocity u crosses a point O. At the same instant another particle F starts from rest from O with a constant acceleration a. The maximum separation between them before they meet is
A
u2/2a
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B
u2/a
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C
u/2a
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D
u/a
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Solution
The correct option is Au2/2a maximum distance will be when both of them have same velocity because after that point of time velocity of particle F will be more then that of particle X so distance between then starts decreasing.
t=ua.
distance covered by X till this time is S1=u×ua
distance covered by F till that time is s2=12a(ua)2=u22a