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Question

A particles is projected with velocity 2gh and at an angle 60o to the horizontal so that it just clears two walls of equal height h which are at a distance 2h from each other. The time taken by the particle to travel between these two walls is

A
22hg
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B
h2g
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C
2hg
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D
2h2g
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Solution

The correct option is C 2hg
Velocity of the particle v=2gh
Angle of projection θ=60o
Horizontal component of velocity vx=vcosθ=2gh×0.5=gh
Time taken by particle to travel between two walls t=2hvx
t=2hgh=2hg

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