Question

A particles move under the effect of a force F = Cx from x = 0 to x = $x_1$. The work done in the process is

• A. $C{x}_1^2$
• B. $\frac{1}{2}C{x}_1^2$
• C. $C{x}_1$
• D. Zero

Answer 1

Answer: (B)

$\frac{1}{2}C{x}_1^2$

F$={\int }_0^{x_1}cxdx=c[\frac{{x_1}^2}{2}-0]=\frac{1}{2}c{x_1}^2$