A particular hydrogen like atom has its ground state Binding Energy=122.4eV. It is in ground state. Then

atomic number is 3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

an electron with 90 ev energy can interact with it and excite it

No worries! We‘ve got your back. Try BYJU‘S free classes today!

An electron of kinetic energy 91.8eV can be brought to almost rest by this atom.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

An electron of KE nearly 2.6 eV may emerge from the atom electron of KE 125ev collides

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A atomic number is 3
$\begin{matrix} Let Atomic number be "z" Binding energy = z^{2} (13.6) \begin{matrix} 122.4 = z^{2} (13 \cdot 6) z^{2} = 9 z = 3 \end{matrix} \end{matrix}$

Suggest Corrections

Similar questions

Q. An electron is in excited state in a Hydrogen like atom. It has a total energy of -3.4 eV, then

Q. An electron collides with a fixed hydrogen atom in its ground state. Hydrogen atom is excited and colliding electron loses of its kinetic energy. Consequently, the hydrogen atom may emit a photon corresponding to largest wavelength of the Balmer series. Minimum possible kinetic energy of colliding electron will be

A photon collides with a stationary hydrogen atom in ground state in an inelastic manner. Energy of the colliding photon is 10.2 eV. Almost instantaneously, another photon collides with same hydrogen atom inelastically with an energy of 15 eV. What will be observed by the detector?

In a hydrogen like atom, electron is in 2nd excited state, the binding energy of fourth state of this atom is 13.6 eV, then

Q. An electron with energy

12.09

eV strikes hydrogen atom in ground state and gives its all energy to the hydrogen atom. Therefore hydrogen atom is excited to __________ state.

Join BYJU'S Learning Program

A particular hydrogen like atom has its ground state Binding Energy=122.4eV. It is in ground state. Then

The correct option is A atomic number is 3 Let Atomic number be "z" Binding energy =z2(13.6)122.4=z2(13⋅6)z2=9z=3

The correct option is A atomic number is 3
$\begin{matrix} Let Atomic number be "z" Binding energy = z^{2} (13.6) \begin{matrix} 122.4 = z^{2} (13 \cdot 6) z^{2} = 9 z = 3 \end{matrix} \end{matrix}$