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Question

A particular reaction at 27ºC for which the change in enthalpy and the change in entropy are both positive is found to be non-spontaneous. The reaction may proceed spontaneously if:

A
the temperature is decreased
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B
the temperature is increased
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C
the temperature is kept constant
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D
it is carried out in an open vessel at 27ºC
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Solution

The correct option is B the temperature is increased
ΔG = ΔH - TΔS
According to this equation,
When ΔH and ΔS are positive and the reaction is non-spontaneous, ΔH is more negative than TΔS.
To make the reaction spontaneous, ΔG needs to become negative. This happens when TΔS increases, i.e. T increases.

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