Question

A particular station of All India Radio, New Delhi broadcasts on a frequency of $1,368kHz$ (kilohertz). The wavelength of the electromagnetic radiation emitted by the transmitter is : [speed of light $c=3.0\times {10}^{8}m{s}^{–1}$]

• A. $21.92\text{cm}$
• B. $219.3\text{m}$
• C. $219.2\text{m}$
• D. $2192\text{m}$

Answer 1

The correct option is B $219.3\text{m}$

Energy of electromagnetic radiation $\left(E\right)$
$=\frac{hc}{\lambda }=h\nu$

So, $\frac{c}{\lambda }=\nu \Rightarrow \lambda =\frac{c}{\nu }$

$\lambda =\frac{3\times {10}^8}{1368\times {10}^3}=219.3m$