A particular transformer is designed to turn 12 V into 240 V and a maximum current of 5 A. What should be the turn ratio for the step-down transformer used?

240: 5

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20: 1

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1: 20

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5: 240

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Solution

The correct option is B 20: 1
$E_{p} = 12 V, E_{s} = 240 V, n = \frac{N_{s}}{N_{p}} = ? \frac{E_{s}}{E_{p}} = \frac{N_{s}}{N_{p}} \Rightarrow \frac{N_{s}}{N_{p}} = \frac{240}{12} = \frac{20}{1} ∴ n = 20 : 1$

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