A passenger is standing 10 m away from a bus. The bus begins to move with constant acceleration of 5 m/s2 away from passenger. With what minimum speed must passenger run to catch bus.
A
10 m/s
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B
8 m/s
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C
12 m/s
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D
5√2m/s
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Solution
The correct option is A 10 m/s
Let man catches bus after time t, and let the bus travels a distance d and achieves a speed v.
Then v=0+5t [For bus] v=10+dt [For man] and d=12×5t2 [For bus]
Solving all we get is d=10m & v=10m/s & t=2s