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Question

A passenger is standing 10 m away from a bus. The bus begins to move with constant acceleration of 5 m/s2 away from passenger. With what minimum speed must passenger run to catch bus.

A
10 m/s
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B
8 m/s
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C
12 m/s
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D
52 m/s
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Solution

The correct option is A 10 m/s

Let man catches bus after time t, and let the bus travels a distance d and achieves a speed v.
Then v=0+5t [For bus]
v=10+dt [For man] and d=12×5t2 [For bus]
Solving all we get is d=10 m & v=10 m/s & t=2 s

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