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Standard XII

Physics

Non Uniform Motion & Avg Velocity

A passenger t...

Question

A passenger train running at a speed of $80$ km/hr leaves the railway station $6$ hours after a good train leaves and overtakes it in $4$ hours. What is the speed of the goods train?

48

km/hr

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60

km/hr

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32

km/hr

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80

km/hr

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Solution

The correct option is C $32$ km/hr
Distance covered by the passenger train in 4 hours $= (80 \times 4) k m = 320 k m$
This is the distance covered by the goods train in 10 hours.
$∴$ Speed of goods train = $\frac{320}{10} k m / h r = 32 k m / h r .$

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A passenger train running at a speed of 80 km/hr leaves the railway station 6 hours after a good train leaves and overtakes it in 4 hours. What is the speed of the goods train?

The correct option is C 32 km/hrDistance covered by the passenger train in 4 hours =(80×4)km=320kmThis is the distance covered by the goods train in 10 hours.∴ Speed of goods train = 32010km/hr=32km/hr.

A passenger train running at a speed of $80$ km/hr leaves the railway station $6$ hours after a good train leaves and overtakes it in $4$ hours. What is the speed of the goods train?

The correct option is C $32$ km/hr
Distance covered by the passenger train in 4 hours $= (80 \times 4) k m = 320 k m$
This is the distance covered by the goods train in 10 hours.
$∴$ Speed of goods train = $\frac{320}{10} k m / h r = 32 k m / h r .$