The correct option is A 25
Let the speed of train be x km/hr.
Distance travelled=300 km
⇒Time taken, t=300x
If the speed is increased by 5 kmph, then the time taken to complete the same distance is given by
T=300x+5.
From question, we have t−T=2.
⇒300x−300x+5=2
⇒300(x+5)−300x=2x(x+5)⇒2x2+10x−1500=0⇒x2+5x−750=0
i.e., x2+30x−25x−750=0
⇒x(x+30)−25(x+30)=0
⇒(x+30)(x−25)=0
⇒x=−30,25
Since speed cannot be negative, the initial speed of the train is 25 kmph.