A passenger train takes one hour less for a journey of 150km if its speed is increased by 5km/hr from its usual speed. Find the usual speed of the train.
Let the usual speed of train be x km/hr
Then, increased speed of the train = (x + 5)km/hr
Time taken by the train under usual speed speed to cover 150 km = hr
Time taken by the train under increased speed to cover 150km =hr
So, it is given that
750=x2+5x
x2+5x−750=0
x2+30x−25x−750=0
x(x+30)−25(x+30)
(x−25)(x+30)
x = 25 or x = - 30
Since, the speed of the train can never be negative
Therefore, the usual speed of the train is x = 25km/hr