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Question

A password of 4 letters is to be formed with vowels alone How many such passwords are possible if
(i) repetition of letters is allowed
(ii) repetition of letters is not allowed?
If A denotes the outcome of (i) and B denotes the outcome of (ii), then find the value of AB.

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Solution

The tasks T12T23T3 AND T4 are about filling the 1st, 2nd, 3rd and 4th slots in the password
(i) The first slot can be filled in 5 ways (a, e, i, o or u) The second can also be filled in 5 ways (with repetition being allowed)
The third and fourth can also be filled in 5 ways each
Using the generalization we get 5×5×5×5=625 passwords
A=625
(ii) The first slot can be filled in 5 ways (a, e, i, o or u) The second slot can be filled in 4 ways (as repetition is not allowed)
The third and fourth in 3 and 2 ways respectively
Thus the total number of possible passwords are 5×4×3×2=120
B=120

AB=625120=505

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