Question

A path of 8 m width runs around the outsider of a circular park whose radius is 17 m. Find the area of the path.

Answer 1

The radius (r) of the inner circle is 17 m.
The radius (R) of the outer circle is 25 m. [Includes path, i.e., (17 + 8)]

Area of the path = $\pi R^2-\pi r^2$
$$\begin{gathered} =\mathrm{\pi }\left(R^2-r^2\right) \\ =\frac{22}{7}\left({25}^2-{17}^2\right) \\ =\frac{22}{7}\times (25-17)(25+17) \\ =\frac{22}{7}\times 8\times 42 \\ =1056{\mathrm{m}}^2 \end{gathered}$$

∴ Area of the path = 1056 m²