A path of uniform width, $2.5$ m. runs around the inside of a rectangular field $30$ m by $27$ m.
Find the area of the path in sq-m

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Solution

The length of the inner rectangle $= 30 - 2 (2.5) = 25 m$
The breadth of the inner rectangle $= 27 - 2 (2.5) = 22 m$
Area of the path $=$ Area of the rectangular field $-$ Area of the inner rectangle
Area of the path $= 30 \times 27 - 25 \times 22 = 810 - 550 = 260 m^{2}$

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A path of uniform width, 2.5 m. runs around the inside of a rectangular field 30 m by 27 m. Find the area of the path in sq-m

The length of the inner rectangle =30−2(2.5)=25mThe breadth of the inner rectangle =27−2(2.5)=22mArea of the path = Area of the rectangular field − Area of the inner rectangleArea of the path =30×27−25×22=810−550=260m2

A path of uniform width, $2.5$ m. runs around the inside of a rectangular field $30$ m by $27$ m.
Find the area of the path in sq-m

The length of the inner rectangle $= 30 - 2 (2.5) = 25 m$
The breadth of the inner rectangle $= 27 - 2 (2.5) = 22 m$
Area of the path $=$ Area of the rectangular field $-$ Area of the inner rectangle
Area of the path $= 30 \times 27 - 25 \times 22 = 810 - 550 = 260 m^{2}$