Question

A path of uniform width, $3$ m, runs around the outside of a square field of side $21$ m. Find the area of the path (in $sqm$).

Answer 1

The dimensions of the outer square containing the square field with the path $=21+2\left(3\right)=27m$
Area of the path $=$ Area of the outer square containing the square field with the path $-$ Area of the square field
Area of the path $=27\times 27-21\times 21=729-441=288m^2$