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Question

A pea plant with pure yellow (YY) and round (RR) seeds were crossed with a plant having pure green (yy) wrinkled (rr) seeds.

If the off-springs of the the F-1 generation are self-pollinated, what would be the phenotypic ratio in F-2 generation?


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Solution

  1. In the experiment, a cross is made between a homozygous plant with yellow round seeds(YYRR) and a homozygous plant with green wrinkled seeds (yyrr).
  2. In the F-1 generation, all the off-springs show yellow round seeds(YyRr).
  3. The F-1 generation off-springs are self-pollinated to obtain F-2 generation where four different types of seed combinations are obtained.
  4. The combination is due to the expression of recessive characters in absence of a dominant factor.
  5. Different combinations obtained in F-2 generation can be seen in Punnett square.

RYRyrYry
RYRRYYRRYyRrYYRrYy
RyRRYyRRyyRrYyRryy
rYRrYYRrYyrrYYrrYy
ryRrYyRryyrrYyrryy

The phenotypic ratio is 9:3:3:1 for round yellow: round green: wrinkled yellow: wrinkled green.


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