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Question

A pebble is thrown vertically upwards from a bridge with an initial velocity of 4.9ms1. It strikes the water after 2s. Height of the bridge is:

A
19.6 m
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B
14.7 m
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C
9.8 m
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D
4.9 m
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Solution

The correct option is C 9.8 m
Option C is correct
s=ut+12at2
u=+4.9m/s
g=9.8m/s2
t=2sec.
s=4.9×212×9.8×(2)2=9.8m
Height is |s|=9.8 m

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