a peice of silver has resistance 1ohm. what will be the resistance of the constantan wire of one third of its lenth and one half of its diameter if the specific resistance of the constantan wire is 30 times than that of the silver?

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Solution

R = pL /A

let the properties of silver be denoted by 1 and properties of constantine is 2

R ₁= 1 ohm
30 p₁= p₂
L₁/3 = L₂
A₁/4 = A2

on comparing we get ,

R₂= 40ohm

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a peice of silver has resistance 1ohm. what will be the resistance of the constantan wire of one third of its lenth and one half of its diameter if the specific resistance of the constantan wire is 30 times than that of the silver?

R = pL /A let the properties of silver be denoted by 1 and properties of constantine is 2 R 1 = 1 ohm 30 p1 = p2 L1 /3 = L2 A1/4 = A2 on comparing we get , R2= 40ohm

R = pL /A

let the properties of silver be denoted by 1 and properties of constantine is 2

R ₁= 1 ohm
30 p₁= p₂
L₁/3 = L₂
A₁/4 = A2

on comparing we get ,

R₂= 40ohm