A pellet of mass 1 g is moving with an angular velocity of 1 rad/s along a circle of radius 1 m the centrifugal force is:
A
0.1 dyne
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B
1 dyne
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C
10 dyne
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D
100 dyne
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Solution
The correct option is D 100 dyne Given that m=1×10−3kg;ω=1rad/s and r=1m Hence, centrifugal force =mω2r=10−3N 1N=105dyne ∴ Centrifugal force = 100 dyne.