A pendulum bob has a speed of 3m/s at its lowest position. The pendulum is 50cm long. The speed of the bob, when the length makes an angle of 60∘ with the vertical, will be (g=10m/s2)
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Solution
Applying work energy theorem: Wg+WT=ΔK mgl(1−cos60∘)=12mv2−12mu2 v2=u2−2gl(1−cos60∘) =9−2×10×0.5(12)=4 ∴v=2m/s