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Question

A pendulum bob of mass m is held in the horizontal position and then released show that the velocity of bob at lowest position is 2gl.

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Solution

Loss in Gravitational potential energy = Gain in Kinetic energy
=mg(l)=12mv2
V=2gl

1010305_1130312_ans_22fb3b0f381f44858e4044bae3904223.png

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