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Question

A pendulum clock giving correct time at a place where g=9.800 m s2 is taken to another place where it loses 24 seconds during 24 hours. Find the value of g at this new place.

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Solution

For the pendulum,

T1T2=(g2g1)

Give that, T2=2 sec, g1=9.8 m/s2

T1=24×3600(24×360024)2

=2×36003599

Now, g2g1=(T1T2)2

g2=(9.8) (35993600)2

=0.795 m/s2


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